Maths Homework (advanced ****)

Frank

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can anyone here help with the following,
3a or b

15x0fmf.png


i know most of you can't i just want to see if anyone can do it.
 
Or you can actually LEARN how to do it, so that you won't fail the class.

That post came from me, an almost 16 year old still in 9th grade, that currently has straight F's with 33%, a 29%, and a 26%.

Jesus, what were you thinking? I HAD A BRAIN? :eek:
 
That post came from me, an almost 16 year old still in 9th grade, that currently has straight F's with 33%, a 29%, and a 26%.

Jesus, what were you thinking? I HAD A BRAIN? :eek:

That explains a lot.
 
For A, try this:

Write down P, Q, and R down in a table. Then write every list of options that P, Q and R can be, true or false. You should have 8 things total. Then write down what you're trying to find, (pVq)^(not qVr), all to the left of the P, Q, and R entries. Write down if these are true or false (For P=True, Q=False and R=False, (pVq) would be satisfied (since P is true) and so would (not qVr), since not q is true, so the equation would be satisfied.

For the equation to be false, either both p and q must be false or not q and r. It is neither tautological (self asserting, IE PVnot P) or contradictory.

EDIT: The equation itself is saying:

(Either p or q are true) AND (Either not q or r are true)
 
For A, try this:

Write down P, Q, and R down in a table. Then write every list of options that P, Q and R can be, true or false. You should have 8 things total. Then write down p V q, (not q) V r, and then what you're trying to find, (pVq)^(not qVr).

Since q and not q can't both happen, this is really just saying p or r. So it is neither a tautology (self asserting statement) or a contradiction.

Why did you gravedig this?... it's over a month old...
 
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